MATH 1071 MatrixApplications2_10:31

# I ax d x i 2 a 1 6 4 2 1 2 30 24 15 23 10 patrick

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Unformatted text preview: 30 24 15 = 23 10 Patrick Newberry D &lt;- equivalent of dividing by (I-A) 3 12 3 .3 .6 .2 .2 .3 5 .6 32 22 21 34 22 5 4 15 30 35 4 90 5 20 32 3 35 300 90 5 = 4 350 5 20 200 Applications of Matrices October 31, 2012 Notes A= how much consumed when you are making the given quantity (produced) X= amount produced D=x-Ax how much is left over to be sold 5 / 10 Routing Problems Notes horizontal- ending point vertical- starting Patrick Newberry w 0 w0 point x B 1 B A= y @2 z 2 x 1 0 1 0 y 2 1 0 1 Applications of Matrices z 1 2 0C C 1A 0 October 31, 2012 7 / 10 Routing Problems Notes 2 0 61 A2 = 6 42 2 Patrick Newberry 1 0 1 0 2 1 0 1 32 2 01 0 76 1 0 76 1 54 2 1 0 20 2 1 0 1 w x y z3 3w 2 2 x9 07 62 7=6 4 15 y 3 z2 0 Applications of Matrices out put 9 after you square the matrix- means that if you are allowed to take two different pathes between points there are nine different routes you can take 2 2 2 3 3 2 6 4 2 37 7 15 5 October 31, 2012 8 / 10 Routing Problems Notes Clicker Check-out: Choose any letter to check out now. Recitation Thursday: Workshop 5 Next Time: Continue Section 6.6: Applications of Matrices Patrick Newberry Applications of Matrices October 31, 2012 10 / 10 Notes...
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