HW#3 Solution

25 ma2 k 35 v this vce is greater than vsat confirming

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Unformatted text preview: ter loop yields iB = (VBB – Vf)/RB = 65 µA. This curve is indicated on the above plot. c. The load line crosses the vCE axis at VCC = 10 V and crosses the iC axis at VCC/RC = (10 V)/(3.9 kΩ) = 2.6 mA. As shown above, this load line intersects the 65 µA curve in the saturation region with vCE ≈ 0.2 V and iC≈ 2.5 mA. 5.111 Inspection of the v- i curve...
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This note was uploaded on 02/13/2014 for the course EE 2230 taught by Professor Staff during the Spring '08 term at LSU.

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