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PASS-nov27

# PASS-nov27 - Problem 1 A steel Rod 0.350 m long and an...

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Problem 1 A steel Rod 0.350 m long and an aluminum rod 0.250 m long, both with the same diameter, are placed end to end between rigid supports with no initial stress in the rods at -20 ° C. The temperature of the rods is now raised to 40 ° C. The length of the combined rod remains the same because of the rigid supports, but the lengths of the original rods do not. a) Find the length of each rod at 40 ° C b) Find the stress in each rod at 40 ° C c) Consider the same problem with same rod dimensions and parameters. The steel rod is on the left side and the aluminum rod is on the right. The rods are now wrapped in perfectly insulating material and the two ends are in direct contact with a heater. The left heater is set at -20C and the right heater is set at 40C. What are the lengths of the steel and aluminum rods respectively? Use: K steel= 50 W(mK)^-1, K aluminum= 237 W(mK)^-1 Calculate the heat flux assuming that the length of the rods is 0.35m and 0.25m respectively. This assumption is fair because the length of the rods change very little relative to the total length.

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Problem 6 Two cubes of equal side length, one of aluminum and the other of copper, are arranged between heat reservoirs at 100 ° C and 0 ° C as shown in diagram a. The heat reservoir at 0 ° C consists of a mixture of water and ice. The heat conducted by the cubes melts 1250 g of ice every 10 minutes. (a) What is the length of the side of a cube? (b) What is the temperature at the junction between the aluminum and copper cubes? (c) How much ice would melt in 10 minutes if the cubes were instead arranged as in diagram b?

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Tips for solving heat engine questions These questions are long, so make sure you give yourself a bit of extra time.
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PASS-nov27 - Problem 1 A steel Rod 0.350 m long and an...

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