2012FallExam3AandBThursdaySolutions

In this case the vertex is given by 3100 since 1 0

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Unformatted text preview: ur at the vertex. In this case, the vertex is given by 3,100 . Since 1 0, this parabola opens upward, so the vertex is a minimum point. In particular, the minimum value is the -value of the vertex; namely, 100. 12A/2B. Find the vertex of the parabola ⇒ 8 4, 16 . 8 4 8. 4 8 4 4 4 16. . 13A/3B. 13A/3B. If 1 2 2. So, deg 14A/4B. If , find the degree of . 1 2 2 1. is as in #13/3 above, find the leading coefficient. The leading coefficient is the coefficient on the highest-degree term, i.e., 2. 4 describe the left- and right-hand behavior of the graph of 15A/5B....
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This document was uploaded on 02/17/2014 for the course MATH 1200 at Ohio University- Athens.

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