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Unformatted text preview: nce (t), so y(t) is time invariant. Problem 2 (Convolution by inspection):
(a) What is the convolution of x2[n] and h2[n], when these signals are given by the following
3 10 , 15 10 5 . y(t) 5 5 3 10 , 15 10 5 5 5 We should use the sifting property of the impulses i.e. for any signal x(t), x(t) convolved with delta(t‐t0) is x(t‐t0) i.e. the original signal shifted to where the impulse is located on the time axis. Thus for part (a): y2[n] = 15x2[n+10] ‐ 5x2[n] + 5x2[n‐5] Substituting for x2[n]: y2...
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This document was uploaded on 02/17/2014.
- Fall '14