3-3_projectiles (1)

# 0 m 0 49t therefore t 2019s since time is equal in

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Unformatted text preview: t’d Solution, ∆dy = v1y ∆ t + ½ a ∆ t² 1y 20.0 m = 0 + 4.9t² – Therefore, t = 2.019s – Since time is equal in each direction, Since S:∆dx = v1xt = 18(2.019) = 36.3 m P: Therefore, the arrow travels 36.3 m before hitting the P: ground. ground. Objects Launched at Angles Objects Harder stuff. Now we need to combine Harder some knowledge. some We can always take the “launch” velocity of We a projectile and break it down from v1 to projectile component form: v1x and v1y component Projectiles Projectiles A few things are important to remember here: – The higher the launch angle, the greater the max height – As a projectile reaches its maximum height, the vertical As velocity (vy) is 0m/s velocity – If the starting and finishing heights are the same (e.g. a If golf ball is hit from the ground and ends up on the ground again) then the total time for the whole situation is TWICE the time taken to reach max height. is – We can use a shortcut formula for max height h = v1y² 2g 2g Everyone now try p. 82 #1...
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