228s13-l04

Sunday february 24 2013 maxima and minima algebra you

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Unformatted text preview: the lines move out and there are fewer of them. d) The angles decrease, but there are still the same number minima / maxima lines. e) I think answer a) is right or wrong. Sunday, February 24, 2013 Maxima and Minima Algebra You can see from the demo & simulation that when you shift the frequency or the distance between the sources the interference pattern does move around. Higher frequencies reduce the angles between the minima and maxima. Since the sources emit light in phase, maxima and minima at the same time, there is constructive interference when at a point these add. This happens when the sources are an integral number of wavelengths different distance from some point. r2 - r1 = mλ, with m = 0, ±1, ±2, ... For minima, we want destructive interference: r2 - r1 = (m+½)λ, with m = 0, ±1, ±2, ... You could also analyze the interference based on the time difference from one source vs. the other to a given point being an integral (or half-integral) number of periods. Sunday, February 24, 2013 Maxima and Minima Algebra Assume that the two sources are in phase. For maxima, we want constructive interference: r2 - r1 = mλ, with m = 0, ±1, ±2, ... For minima, we want destructive interference: r2 - r1 = (m+½)λ, with m = 0, ±1, ±2, ... Sunday, February 24, 2013 Water Analog For maxima, we want constructive interference: r2 - r1 = mλ, with m = 0, ±1...
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This document was uploaded on 02/18/2014 for the course PHYS 228 at Rutgers.

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