The gs will have qrs1 and e111 3222ml2 what is the

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Unformatted text preview: 3 ... and similar in the y and z directions. Then Eqrs = Eq + Er + Es = (q2+r2+s2)ħ2π2/2mL2. The g.s. will have q=r=s=1, and E111 = 3ħ2π2/2mL2. Monday, April 1, 2013 iClicker Eqrs = Eq + Er + Es = (q2+r2+s2)ħ2π2/2mL2. The g.s. will have q=r=s=1, and E111 = 3ħ2π2/2mL2. What is the energy of the 1st excited state? How many of them are there? a) E2 = Egs, 1 b) E2 = 2Egs, 1 c) E2 = 4Egs, 1 d) E2 = 2Egs, 3 e) E2 = 4Egs, 3 Monday, April 1, 2013 Degenerate States States of the same energy are called "degenerate states". Is is possible to break the degeneracy by having all 3 sides of the box different lengths, so that Eqrs = Eqx + Ery + Esz = (q2+r2+s2)ħ2π2/2mL2 → Eqrs = Eqx + Ery + Esz = (q2/Lx2 +r2/Ly2 +s2/Lz2) ħ2π2/2m. Monday, April 1, 2013 Probability Distributions Again in 3D QM, as in the 1D case, the probability of finding a particle at some point x0, y0, z0 in space is given by ψ*ψ = |ψ|2 at that point. Note an odd feature of QM: the particle in, e.g., the ψ2,1,1 state can never be found in the x=L/2 plane...
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This document was uploaded on 02/18/2014 for the course PHYS 228 at Rutgers.

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