Ni2 24 1013 2 192 1011 cm 3 15 p 3 10 n 2 1015

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Unformatted text preview: 1014 4.36 (a) Consider a germanium semiconductor at T = 300 K. Calculate the thermal equilibrium electron and hole concentrations for (i) Nd = 2 X 1015 cm- 3, Na = 0, and (ii) Na = 1016 cm- 3, Nd = 7 x 1015 cm- 3. (b) Repeat part (a) for GaAs. (c) For the case of GaAs in part (b), the minority concentrations are on the order of 10- 3 cm- 3. What does this mean physically? (a) (i) n = 2 × 1015 cm −3 . ni2 (2.4 × 1013 )2 p= = = 2.88 × 1011 cm −3 15 n 2 × 10 p = 1016 − 7 × 1015 = 3 × 1015 cm −3 (ii) (b) (i) n= . ni2 (2.4 × 1013 )2 = = 1.92 × 1011 cm −3 15 p 3 × 10 n = 2 × 1015 cm −3 (ii) 5.2 ni2 (1...
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