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Unformatted text preview: atomic density of 3 ×
1022 cm-3. Each atom has a polarizability of 5 × 10-37 F-cm2. Find the internal
electric field when an axial field of 10 mV/cm is applied. The internal electric field is related to the applied electric field through the
boundary condition found from Gauss’ Law:
ε int Eint = ε 0 Eappl .
Hence, Eint = ε0
1+ χ Now, the susceptibility is given by the electronic polarization through the
equations on p. 298 as
ε 0 E appl
The polarizability is the polarization dipole divided by the ap...
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- Fall '14