Unformatted text preview: atomic density of 3 ×
1022 cm3. Each atom has a polarizability of 5 × 1037 Fcm2. Find the internal
electric field when an axial field of 10 mV/cm is applied. The internal electric field is related to the applied electric field through the
boundary condition found from Gauss’ Law:
ε int Eint = ε 0 Eappl .
Hence, Eint = ε0
1
Eappl =
Eappl. .
ε int
1+ χ Now, the susceptibility is given by the electronic polarization through the
equations on p. 298 as
Np
.
χ=
ε 0 E appl
The polarizability is the polarization dipole divided by the ap...
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This document was uploaded on 02/19/2014.
 Fall '14

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