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PRE-LAB QUESTIONS1.When 3.0 kg of water is warmed from 10 °C to 80 °C, how much heat energy is needed?4.18j/gc x 3000g x 70c = 877800 Joules or 877.8 Kj or Calories2.A calorimeter contains 100 g of water at 39.8 ºC. A 8.23 g object at 50 ºC is placed insidethe calorimeter. When equilibrium has been reached, the new temperature of the water and metal object is 40 ºC. What type of metal is the object made from?magnesium. (Mg)Enthalpy and Specific Heat
EXPERIMENT 1: DETERMINATION OF SPECIFIC HEAT OF A METALData SheetTable 2: MassMass (g)Water54.1Unknown MetalStrip19.6Table 3: Specific Heat DataTime (minutes)Temperature (°C) Trial 1Trial 2Trial 3Initial22.522.522.55 minutes23.022.523.06 minutes23.523.023.57 minutes24.523.524.08 minutes25.025.024.59 minutes25.025.025.010 minutes25.025.025.0Average Specific Heat Capacity of theUnknown Metal: 100°CPost-Lab QuestionsEnthalpy and Specific Heat
1.Why is ΔTmetal < 0? It less than zero because hot metal loss heat to water which makes the temperature lower. 3.Why is ΔTwater > 0 ? It is greater than because water gains heat to water which makes the temperature is increase.4.A metal sample weighing 43.5 g and at a temperature of 100.0 °C was placed in 39.9 g of water in a calorimeter at 25.1 °C. At equilibrium the temperature of the water and