ws1_work_flux_soln

# Hence the ow rate va cos va even though the area a is

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Unformatted text preview: oss-section, but it works for any cross-section. Hence the ﬂow rate vAθ cos θ = vA. Even though the area Aθ is larger than A (by a factor of cos θ), the height/width of the slanted Page 1 of 3 Math 1920 Workshop 1: Work and Flux Solutions column is smaller than v by the same factor. Hence the volumes and ﬂow rates, in part a and b are the same. One can also imagine a deck of cards, with cards laid horizontally along the arrows shown in the ﬁgure. Deck in ﬁgure (b) is a displaced version of the deck in ﬁgure (a), and hence has the same volume. c) In part a, the velocity ﬁeld is v = vˆ and the area vector S = Aˆ. The ﬂux is v · S = vA....
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## This homework help was uploaded on 02/16/2014 for the course MATH 1920 taught by Professor Pantano during the Spring '06 term at Cornell.

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