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Finite Lab 5 Solutions

# Finite Lab 5 Solutions - b C but not B 5 14 = 19 5 a 10 58...

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Math 120 Spring 2008 Brodnick Lab #5: 6.1 – 6.3 Solutions 1. A C = {1, 5, 8} {1, 2, 3, 4, 6, 7} = {1} 2. ) ( C B A = {1, 2, 3, 4, 6, 7} {3, 7} = {1, 2, 3, 4, 6, 7} 3. ] ) [( B A C = [({1, 5, 8} A ) {0, 2, 4, 6}] = ({0, 1, 5, 8} {0, 2, 4, 6}) = {0} = {1, 2, 3, 4, 5, 6, 7, 8} 4. x = 8 y = 12 z = 19 w = 5 a. A or B : 17 + 21 + 8 + 5 + 12 + 10 = 73
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Unformatted text preview: b. C but not B : 5 + 14 = 19 5. a. 10 + 58 + 54 + 32 + 8 + 80 + 131 = 373 b. 8 + 80 + 131 = 219 c. 131 d. 10 + 54 + 32 = 96 6. 10 × 9 × 10 × 10 = 9000 ATM codes 7. 2 × 3 × 6 = 36 classifications of people polled A B C S 19 17 21 10 14 5 8 12 B L D S 8 10 32 131 54 80 58...
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