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Finite Lab 6 Solutions

Finite Lab 6 Solutions - A n 5 No these events are not...

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Math 120 Spring 2008 Brodnick Lab #6: 6.4, 7.1, & 7.2 Solutions 1. at most 3 orange: 0, 1, 2, or 3 orange: 7C0 15C12 + 7C1 15C11 + 7C2 15C10 + 7C3 15C9 = 248,248 2. 12P4 = 12 × 11 × 10 × 9 = 11,880 3. A B 4. a. B A b. {(2,1)(2,2)(2,3)(2,4)(2,6)} 5 ) ( = B
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Unformatted text preview: A n 5. No, these events are not mutually exclusive – they can happen simultaneously 6. 250 65 7. 150 45 8. Outcome HH HT TT Probability 750 302 750 226 750 222 9. at most 1 head: 0 or 1 head: 750 448 750 222 226 = + 10. {(1,6)(2,5)(3,4)} 21 3...
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