Finite Lab 6 Solutions

Finite Lab 6 Solutions - A n 5. No, these events are not...

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Math 120 Spring 2008 Brodnick Lab #6: 6.4, 7.1, & 7.2 Solutions 1. at most 3 orange: 0, 1, 2, or 3 orange: 7C0 15C12 + 7C1 15C11 + 7C2 15C10 + 7C3 15C9 = 248,248 2. 12P4 = 12 × 11 × 10 × 9 = 11,880 3. A B 4. a. B A b. {(2,1)(2,2)(2,3)(2,4)(2,6)} 5 ) ( = B
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Unformatted text preview: A n 5. No, these events are not mutually exclusive they can happen simultaneously 6. 250 65 7. 150 45 8. Outcome HH HT TT Probability 750 302 750 226 750 222 9. at most 1 head: 0 or 1 head: 750 448 750 222 226 = + 10. {(1,6)(2,5)(3,4)} 21 3...
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