chapter 5

# Factor2x2x6

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Unformatted text preview: ) From the second term, you have a &quot;–b&quot; left over: 2(x – y) – b(x – y) = (x – y)(2 – b) Factor x(x – 2) + 3(2 – x). = x(x – 2) + 3(2 – x) =x(x ­ 2) + 3(­x + 2) = x(x­2) – 3(x – 2) = (x – 2)(x – 3) Factor xy – 5y – 2x + 10. = xy – 5y – 2x + 10 What can factor out of the first pair? I can take out a &quot; y&quot;: = y(x – 5) – 2x + 10 What can factor out of the second pair? Take out a &quot;–2&quot;: = y(x – 5) – 2(x – 5) = (x – 5)(y – 2) A &quot;quadratic&quot; is a polynomial that looks like &quot;ax2 + bx + c&quot;, where &quot;a&quot;, &quot;b&quot;, and &quot;c&quot; are just numbers. For the easy case of factoring, you will find two numbers that will not only multiply to equal the constant term &quot;c&quot;, but also add up to equal &quot;b&quot;, the coefficient on the x­term. For instance: Factor x2 + 5x + 6. Factoring Trinomials Factor x2 + 5x + 6. We need to find factors of 6 that add up to 5. Since 6 can be written as the product of 2 a...
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