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Unformatted text preview: nd 3, and since 2 + 3 = 5, then I'll use 2 and 3. From multiplying polynomials we know that this quadratic is formed from multiplying two factors of the form "(x + m)(x + n)", for some numbers m and n. So draw the parentheses, with an "x" in the front of each: (x )(x ) Then write in the two numbers that I found above: (x + 2)(x + 3) The answer is: x2 + 5x + 6 = (x + 2)(x + 3) Factor x2 + 7x + 6. x2 + 7x + 6 = (x + 1)(x + 6)
Factor x2 – 7x + 6. x2 – 7x + 6 = (x – 1)(x – 6)
Factor x2 – 5x + 6. x2 – 5x + 6 = (x – 2)(x – 3)
Factor x2 + 5x + 6. x2 + 5x + 6 = (x + 2)(x + 3) Note that you can use clues from the signs to determine which factors to use, as I did in this last example above: ax2 + bx + c If c is positive, then the factors you're looking for are either both positive or else both negative.
If b is positive, then the factors are positive
If b is negative, then the factors are negative.
In either case, you're looking for factors that add to b. If c is negative, then the factors you're looking for are of a...
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