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Unformatted text preview: tor 12y2 – 5y. In this case, no number is a common factor between the two terms (specifically, the 12 and the 5 share no common numerical factor), but you can still divide out a common variable factor of &quot;y&quot; from each of the two terms. 12y2 – 5y = y( ) In the first term, you have the &quot;12&quot; and the other &quot;y&quot; factor left over: 12y2 – 5y = y(12y ) In the second term, you have the &quot;5&quot; left over: 12y2 – 5y = y(12y – 5) Factor 2(x – y) – b(x – y). This may look different from what you’ve done above, but really it's not. The two terms, 2(x – y) and – b(x – y), do indeed have a common factor; namely, the parenthetical factor x – y. This may be different from what you're used to seeing referred to as being a &quot;factor&quot;, but the factorization process works just the same as before. First, take the common factor out front: 2(x – y) – b(x – y) = (x – y)( ) From the first term, you have a &quot;2&quot; left over: 2(x – y) – b(x – y) = (x – y)(2...
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This document was uploaded on 02/18/2014.

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