Lets sketch the polynomial px x 3 3x 2 x 3 over the

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Unformatted text preview: ch data point, then we are confident that we have the correct answer. The Interpolating Polynomial Enter the x - and y -values of the data points (−3, 0), (−2, −3), (0, 3), and (2, −15) in the vectors x and y. >> x=[-3 -2 0 2]; >> y=[0 -3 3 -15]; The minimum and maximum x -values of the set of data points are −3 and 2, respectively. Let’s sketch the polynomial p(x) = −x 3 − 3x 2 + x + 3 over the interval [−4, 3]. This will ensure that each of the given data points is visible in our final plot. The following commands should produce a graph similar to that in Figure 4. >> >> >> >> p=[-1 -3 1 3]; xp=linspace(-4,3); % 100 equally spaced points from -4 to 3 yp=polyval(p,xp); plot(x,y,’ro’,xp,yp,’-’) Matlab’s plot command is an extremely flexible tool. In this case, note that we are creating two plots with one command. In general, the command plot(x1,y1,s1,x2,y2,s2,...,xN,yN,sN) will draw N plots: the plot of y1 versus x1, the plot of y2 versus x2, and finally, the plot of yN versus xN. Line styles, markers, and colors are defined for each plot in the strings 4 s1, s2,. . . ,sN. title page contents previous page next page back print doc close 4 In Matlab, ’ro’ is an example of a string. Note that strings are delimited by single apostrophes. exit 20 The 10 Interpolating 0 Polynomial −10 −20 −30 −40 −50 −4 −2 0 2 title page 4 Figure 4 The interpolating polynomial must pass through each data point. contents previous page The Vandermonde Matrix Suppose that you wish to find a fourth degree interpolating polynomial that passes through the points (x1 , y1 ), (x2 , y2 ), (x3 , y3 ), (x4 , y4 ), and (x5 , y5 ). If you substitute each of these points in the polynomial y = ax 4 + bx 3 + cx 2 + dx + e, you will arrive at the following system of linear equations. 3 4 2 ax1 + bx1 + cx1 + dx1 + e = y1 3 4 2 ax4 + bx4 + cx4 + dx4 + e = y4 3 4 2 ax5 + bx5 + cx5 + dx5 + e = y5 back print doc 3 4 2 ax2 + bx2 + cx2 + dx2 + e = y2 3...
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