sample-midterm2-with-solutions-v2

F x 20 x3 since f 1 20 0 f 1 1 5 3

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Unformatted text preview: 7. So a = -3 and b = 7 for (1,6) to be a point of inflection for the given curve. Q12. Use the second derivative test to find the local maximum and minimum values of f ( x) = x5 - 5 x + 3 . Solution f '( x) = 5 x 4 - 5 Þ 5( x 4 - 1) = 0 Þ 5( x 2 + 1)( x 2 - 1) = 0 \ x = 1, -1 are the critical numbers. f ''( x) = 20 x3 Since f ''(1) = 20 > 0, f (1) = 1 - 5 + 3 = -1 is a local minimum. Since f ''(1) = -20 < 0, f (-1) = -1 + 5 + 3 = 7 is a local maximum. Q13. Sketch the graph of a function whose first and second derivatives are both pos...
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This document was uploaded on 02/19/2014 for the course MATH Math 113/1 at Grant MacEwan University.

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