lecture13+popgen+2

3 f a1a2 305006 f a2a2 55001 total 10 alleles

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Unformatted text preview: 50 2N individuals 30 A2A2 15 A1A2 A1A2 A1A2 A1A1 A1A2 A1A1 A1A1 A1A1 A2A2 A1A1 A1A2 A1A2 A1A2 A1A2 A1A2 A1A2 A1A2 A1A2 A1A2 A1A2 A1A2 A1A2 A1A1 A1A2 A1A2 A1A2 A1A2 A1A1 A1A1 A1A2 A1A2 A1A1 A1A2 A1A2 A1A1 A1A2 A2A2 A1A1 A1A2 A1A1 A1A2 A1A1 A1A1 A2A2 A2A2 A1A2 A1A2 A1A1 A1A2 Genotypes: f (A1A1)= 15/50= 0.3 f (A1A2)= 30/50=0.6 f (A2A2)= 5/50=0.1 Total = 1.0 Alleles: p = f(A1)= ((2x15)+30)/ 100=0.6 q= f(A2)= ((2x5)+30)/100= 0.4 p+q = 1 Wha...
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This document was uploaded on 02/19/2014.

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