3325p11hs d waiting line

044 and f 998 average number of printers working for

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: rvice a printer in 2 hours (T) Printer downtime costs $120/hour Technician costs $25/hour 2 Service factor: X = = .091 (close to .090) 2 + 20 For M = 1, D = .350 and F = .960 For M = 2, D = .044 and F = .998 Average number of printers working: For M = 1, J = (5)(.960)(1 - .091) = 4.36 For M = 2, J = (5)(.998)(1 - .091) = 4.54 D – 47 Limited-Population Example Cost/Hr for Each of 5Average Number Average Cost/Hr 20 hours (U) of use printers requirefrepair after Printers or Downtime Number of Total One technician can service a printer in 2 Technicians hours (T) Technicians Down (N - J) (N - J)$120 ($25/hr) Cost/Hr Printer downtime costs $120/hour 1 .64 $25.00 $101.80 Technician costs $25/hour $76.80 2 = .091 (close to .090) $55.20 $50.00 2 + 20 For M = 1, D = .350 and F = .960 For Service factor: .46 = X Service 2 $105.20 For M = 2, D = .044 and F = .998 For Average number of printers working: For M = 1, J = (5)(.960)(1 - .091) = 4.36 For For M = 2, J = (5)(.998)(1 - .091) = 4.54 For D – 48 Other Queuing Approaches The single-phase models cover many queuing situations Variations of the four single-phase systems are possible Multiphase models exist for more complex situations D – 49...
View Full Document

This document was uploaded on 02/19/2014.

Ask a homework question - tutors are online