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3325p11hs d waiting line

# 044 and f 998 average number of printers working for

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Unformatted text preview: rvice a printer in 2 hours (T) Printer downtime costs \$120/hour Technician costs \$25/hour 2 Service factor: X = = .091 (close to .090) 2 + 20 For M = 1, D = .350 and F = .960 For M = 2, D = .044 and F = .998 Average number of printers working: For M = 1, J = (5)(.960)(1 - .091) = 4.36 For M = 2, J = (5)(.998)(1 - .091) = 4.54 D – 47 Limited-Population Example Cost/Hr for Each of 5Average Number Average Cost/Hr 20 hours (U) of use printers requirefrepair after Printers or Downtime Number of Total One technician can service a printer in 2 Technicians hours (T) Technicians Down (N - J) (N - J)\$120 (\$25/hr) Cost/Hr Printer downtime costs \$120/hour 1 .64 \$25.00 \$101.80 Technician costs \$25/hour \$76.80 2 = .091 (close to .090) \$55.20 \$50.00 2 + 20 For M = 1, D = .350 and F = .960 For Service factor: .46 = X Service 2 \$105.20 For M = 2, D = .044 and F = .998 For Average number of printers working: For M = 1, J = (5)(.960)(1 - .091) = 4.36 For For M = 2, J = (5)(.998)(1 - .091) = 4.54 For D – 48 Other Queuing Approaches The single-phase models cover many queuing situations Variations of the four single-phase systems are possible Multiphase models exist for more complex situations D – 49...
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