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Unformatted text preview: ll cylinder whose
axis is perpendicular to the
plane for the Gaussian surface Field Due to a
Plane of Charge
• E must be perpendicular
to the plane and must
have the same
magnitude at all points
equidistance from the
• Choose a small cylinder
whose axis is
perpendicular to the
plane for the Gaussian
surface Procedure for Gauss s law problems:
1. Identify the symmetry, and choose a gaussian surface
that takes advantage of it (with surfaces along surfaces of
2. Draw the surface.
3. Use the symmetry to find the direction of E.
4. Evaluate the flux by integrating.
5. Calculate the enclosed charge.
6. Solve for the field. Properties of a Conductor in Electrostatic
• The electric field is zero everywhere inside the conductor
• If an isolated conductor carries a charge, the charge
resides entirely on its surface
• The electric field just outside a charged conductor is
perpendicular to the surface and has a magnitude of σ/εo
• On an irregularly shaped conductor, the surface charge
density is greatest at locations where the radius of
curvature is the smallest Property 1: Einside = 0
• Consider a conducting slab in
an external field E
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- Winter '13