Unformatted text preview: ll cylinder whose
axis is perpendicular to the
plane for the Gaussian surface Field Due to a
Plane of Charge
â€¢â€¯ E must be perpendicular
to the plane and must
have the same
magnitude at all points
equidistance from the
plane
â€¢â€¯ Choose a small cylinder
whose axis is
perpendicular to the
plane for the Gaussian
surface Procedure for Gauss s law problems:
1.â€¯ Identify the symmetry, and choose a gaussian surface
that takes advantage of it (with surfaces along surfaces of
constant field).
2.â€¯ Draw the surface.
3.â€¯ Use the symmetry to find the direction of E.
4.â€¯ Evaluate the flux by integrating.
5.â€¯ Calculate the enclosed charge.
6.â€¯ Solve for the field. Properties of a Conductor in Electrostatic
Equilibrium
â€¢â€¯ The electric field is zero everywhere inside the conductor
â€¢â€¯ If an isolated conductor carries a charge, the charge
resides entirely on its surface
â€¢â€¯ The electric field just outside a charged conductor is
perpendicular to the surface and has a magnitude of Ïƒ/Îµo
â€¢â€¯ On an irregularly shaped conductor, the surface charge
density is greatest at locations where the radius of
curvature is the smallest Property 1: Einside = 0
â€¢â€¯ Consider a conducting slab in
an external field E
â€¢â€...
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This document was uploaded on 02/21/2014 for the course CHEM 110A 110a at UCLA.
 Winter '13

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