ECE 81_hw11_solutions

ECE 81_hw11_solutions - ECE 81 Lehigh University 03/02/2007...

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ECE 81 Lehigh University 03/02/2007 HW #11 ± P5.53: Z = 100 – 50j = 111.8 -26.56° I = 15 2 30° = 21.21 30°A Æ Capacitive load since “– 50j” ~ “– j/C ω Æ θ = -26.56° Æ Power factor = cos( θ ) = cos(-26.56) = 0.8944 = 89.44 % Æ P = V RMS * I RMS * cos( θ ) = 22500.3 W V = 2371.6 3.44° V V RMS = V/ 2 = 1677 I RMS = I/ 2 = 15 Æ Q = V RMS * I RMS * sin( θ ) = - 11247.67 VAR Solutions 1/2 HW11
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ECE 81 Lehigh University 03/02/2006 ± P5.60: ω = 377 Zeq = 1/(1/R + 1/jL ω + jC ω ) = 1/(0.02 – 0.001535j) = 50
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This homework help was uploaded on 04/07/2008 for the course ECE 081 taught by Professor Frey during the Spring '07 term at Lehigh University .

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ECE 81_hw11_solutions - ECE 81 Lehigh University 03/02/2007...

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