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266 t acb 0766 p 2000 n 2 or

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Unformatted text preview: ond cable CAD, which passes over the pulley A and supports a load P. Determine (a) the tension in the cable ACB, (b) the magnitude of load P. SOLUTION Free­Body Diagram: Pulley C Σ Fx = 0: T ACB (cos 30 ° − − cos 50 ° ) P cos 50 ° = 0 P = 0.3473 T ACB (1) or + T ACB (sin 30 ° + sin 50 ° ) Σ = 0: Fy P sin 50 ° − 2000 N = 0 1.266 T ACB + 0.766 P = 2000 N (2) or (a) Substitute Equation (1) into Equation (2): ( 1.266 T ACB + 0.766 0.3473 T ACB )= 2000 N T ACB = 1305.5 N Hence: T ACB = 1306 N (b) Using (1) P = 0.3473 1( 06 N 3 dc217. 4shared. com/ doc/ AOPLVdUr/ prev iew . html )= 453.57 N P = 454 N 4/ 11 2/ 6/ 14 / usr/ hos...
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