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67lb fz 491 lb f y 420lbc s20 o f y 395

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Unformatted text preview: g_files4/ main/ prev iew s/ doc431728704/ prev iew 75 P R O B L E M 2 . 7 4 Determine ( a) the x, y, and z components of the 420­lb force, (b) the angles θ x, θ y, and θ z that the force forms with the coordinate axes. SOLUTION ( a) Fx = − (420 lb s)n 20 sin° 70 i ° = − 134.985 lb F x = − 135.0 lb ° Fz = (420 lb s)n 20 cos 70 i ( b) ° = 49.131 lb cos θ x = ° = 394.67 lb Fz = + 49.1 lb F y = (420 lb c) s 20 o F y = + 395 lb − 134.985 420 θ = 108.7 ° x 394.67 cos θ y = 420 θ y = 20.0 ° z = 83.3 ° 49.131 cos θ z = 420 dc217. 4shared. com/ doc/ AOPLVdUr/ prev iew . html θ 6/ 11 2/ 6/ 14 / usr/ hosting_files4/ main/ prev iew s/ doc431728704/ prev iew 76 P R O B...
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