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Why what is the relationship of this m to l from the

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Unformatted text preview:  U so A  M 1 U and 211 M  L 1. ii) Changing a 23 to what value would cause A If a 23  2 we obtain 1 not to exist? 11 1100 1 1 1 1 00 11 1 1 00 01 2010 0 1 2 0 10 01 1 0 10 21 0 0 1 2 201 00 0 211 001 and A is singular. 4 001 5. (8 pts) If we know that 100 0 2 0 101 100 11 110 A 010 1 0 0 1 , solve 0 Ax  1 1 (Hint: first multiply both sides of Ax  b on the left by P, do not calculate A !) 0 We have PA  LU. Now if Ax  0 we have PAx  P 1 0 2 0 101 0 0 1 Consider Lc  110 x 11 0 2 0 0 0 1 1 1 c 1 1 ; We have c  0 2 1 2 so 1 1 xc 0 0 101 1 1 1 100 Ux  1 11 110 LUx  1  1 1 100 1 1 so x  1 1 5...
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