Lecture Notes 9_Reactive

1 for a capacitor i c dv so dt w c e11 analysis of

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Unformatted text preview: ideal). The average value of x is aV ⇒ the average value of y must also be aV . The average current through R is aV so, since the average current through R C must be zero, the average current iL must also be aV R . C dy = iL − iR ⇒ if C is large, then the variations in y will be very small. dt E1.1 Analysis of Circuits (2013-3717) Capacitors and Inductors: 9 – 10 / 12 Power and Energy 9: Capacitors and Inductors • Capacitors • Types of Capacitor • Inductors • Passive Components • Series and Parallel Electrical power absorbed by any component at the instant t is v (t) × i(t). Inductors • Series and Parallel Capacitors • Current/Voltage Continuity • Average Current/Voltage • Buck Converter • Power and Energy • Summary E1.1 Analysis of Circuits (2013-3717) Capacitors and Inductors: 9 – 11 / 12 Power and Energy 9: Capacitors and Inductors • Capacitors • Types of Capacitor • Inductors • Passive Components • Series and Parallel Electrical power absorbed by any component at the instant t is v (t) × i(t). t2 So total energy absorbed between times t1 and t2 is W = t=t vi dt....
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This document was uploaded on 02/20/2014 for the course EE 101 at WVU.

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