2.01.06 L46 - February 11, 2008 Lecture 4: Mendelian...

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 May 11, 2009 Lecture 4: Mendelian Genetics 2 Conclusions of Dihybrid Cross: 9:3:3:1 Probability Rules Probability of heads: ½ Of tails:1/2 Of both: 1 Of 2 heads: ½ x ½ = ¼ Sum rule: p(of A or B) = pA + Pb Product Rule: p(of A  Example: SsYy x SsYy o Round, yellow S_Y_ ¾ x ¾ =  9 /16 o Round, yellow S_yy ¾ x ¾ =  3 /16 o Round, yellow ssY_ ¾ x ¾ =  3 /16 o Round, yellow ssyy ¾ x ¾ =  1 /16 LEARN TRIHYBRID RATIO!! Non-Independent Assortment Genes lie on same chromosome (1:2:1 ratio) AB ab A B AB/AB AB/ab ab AB/ab Ab/ab 1:2:1 ration ::::::::::::::::::::: THREE TYPES OF DOMINANCE :::::::::::::::::::: Codominance One isn’t dominant over the other Cd is dotted allele, Cs is spotted allele Example: CdCd x CsCs o Phenotype is both spotted and dotted  Another Example: Sickle Cell Anemia Incomplete Dominance
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2.01.06 L46 - February 11, 2008 Lecture 4: Mendelian...

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