E of the mis and that variance has k 1 degrees of

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Unformatted text preview: fewer squares that are independent of each other. For SStreatment, every raw 2 score contributes a square of the form ( M i " M ) , where Mi is the mean of whichever treatment level that score came from. However, since there are only k measurements, meaning only k different Mis, there are only k unrelated squares that go into SStreatment (each one gets repeated n times). Furthermore, because the grand mean is in the formula and it ! depends on the Mis, one of those degrees of freedom disappears. Therefore SStreatment has k – 1 degrees of freedom. Another way to see this is to notice that SStreatment is just a multiple of the variance...
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This document was uploaded on 02/25/2014 for the course PSYC 3101 at Colorado.

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