{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

PS_6_Solutions

# Finally 010 1107 984 763 5 1895 1107 13april2011

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 4 76,3/5 1035,9/7 2 / ,/ 1,895 ,/ 1 , 1 1,895. Finally, , 0,10 110,7 98,4 76,3 5 1,895 110,7 13 April 2011 1035,9 7 98,4 76,3 5 1,895 11,90 36,52 1035,9 7 0,90 0,90. Then, 11,90, 36,52 is a 90% confidence interval for . Observe that, the interval includes value 0, which indicates that the population means of the two samples can be same. Question 3) As we know the test statistic for / is /σ ~ /σ / A 90% confidence interval for / can be calculated as , /σ /σ 4, 6 σ σ 76,3/1035,9 4,53 0,0162 / / 4, 6 , / / . , / σ σ 76,3 1035,9 σ σ , , Then, 0,0162, 0,4537 is the 90% confidence interval for / value 1, our assumption that in Question 2 is valid with 3 6,4 6,16 0,4537 4, 6 1 1 0,10 0,90 0,90. . Since the interval does not include 0,10 level of significance....
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online