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head distance for vehicles in queue (mine is 20 ft) The total queue length in miles is 1058.5 * 20 = 21170ft/5280 (ft/mi) = 4 miles To find average delay, you need to find total delay first (the area within the queue diagram), to do that you have to find total time and total number of vehicles first. The time for queue to clear, t, is the time where arrival and service curves become equal at the tip of the shape: 66.7*5 + 50(t
5) = 25*15 + 80*(t
27)
1868 = 30 t t = 62.27 min Total number of vehicles in the queue: 66.7*5 + 50 *(62.27
5) = 3,197 vehicles Calculate the area...
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 Fall '10
 OZTURK
 pH, $30, the00, $64,317, 21170ft, 36690ft, VMS00

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