Hw#13

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ead ­to ­head distance for vehicles in queue (mine is 20 ft) The total queue length in miles is 1058.5 * 20 = 21170ft/5280 (ft/mi) = 4 miles To find average delay, you need to find total delay first (the area within the queue diagram), to do that you have to find total time and total number of vehicles first. The time for queue to clear, t, is the time where arrival and service curves become equal at the tip of the shape: 66.7*5 + 50(t ­5) = 25*15 + 80*(t ­27)  1868 = 30 t  t = 62.27 min Total number of vehicles in the queue: 66.7*5 + 50 *(62.27 ­5) = 3,197 vehicles Calculate the area...
View Full Document

This document was uploaded on 02/25/2014 for the course CEE 207 at Lehigh University .

Ask a homework question - tutors are online