Antwoorden_Tentamen_Statica_Januari_2010

14 uitwerkingen tentamen statica 1 wb1114 28012010

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: (trek) S CH S GH S CG S FG = −101,8234 kN (druk) = −72 kN (druk) = 60 kN (trek) = −80, 4984 kN (druk) Pag. 1/4 Uitwerkingen tentamen Statica-1 (wb1114) 28.01.2010 Opgave 2 Oplegreacties WAB = 1200 ⋅ 6 = 7, 2 kN WCE = 1800 ⋅ 8 = 14, 4 kN ⎛2⎞ ⎝⎠ ⎛6⎞ β = tan −1 ⎜ ⎟ = 36,8699° ⎝8⎠ α = tan −1 ⎜ ⎟ = 18, 4349° 6 ∑M ∑F x ∑F y D = 0 : TCE ⋅ sin β ⋅ 8 − WAB ⋅ 3 = 0 TCE = 4,5 kN = 0: Dx − TCE ⋅ sin β = 0 Dx = 2, 7 kN = 0: Dy − WAB − WCD − TCE ⋅ cos β = 0 Dy = 25, 2 kN Vrijlichaamsschema van balk AB ∑M ∑F x ∑F y A = 0 : TBC ⋅ sin α ⋅ 6 − WAB ⋅ 3 = 0 TBC = 11,3842 kN = 0: Ax − TBC ⋅ cos α = 0 Ax = 10,8 kN = 0: Ay − WAB + TBC ⋅ sin α = 0 Ay = 3, 6 k...
View Full Document

This document was uploaded on 02/26/2014 for the course MECH 2300 at Delft University of Technology.

Ask a homework question - tutors are online