Antwoorden_Tentamen_Statica_Januari_2010

T1 48246 kn t2 51808 kn pag 34 uitwerkingen tentamen

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Unformatted text preview: T2 x = 0 5 = T2 ⋅ 0, 4472 11,1803 10 T2 z = T2 ⋅ = T2 ⋅ 0,8944 11,1803 T2 y = T2 ⋅ ∑M ∑M y = 0 : Px ⋅ 5 − T1x ⋅10 = 0 3,9392 ⋅ 5 − (T1 ⋅ 0, 4082 ) ⋅10 = 0 T1 = 4,8246 kN x = 0 : T2 y ⋅10 − T1 y ⋅10 − Py ⋅ 5 = 0 (T2 ⋅ 0, 4472 ) ⋅10 − (T1 ⋅ 0, 4082 ) ⋅10 − 0, 6946 ⋅ 5 = 0 T2 = 5,1808 kN Antw. T1 = 4,8246 kN T2 = 5,1808 kN Pag. 3/4 Uitwerkingen tentamen Statica-1 (wb1114) 28.01.2010 Opgave 4 Vrijlichaamsschema van de hele balk: R = 30 ⋅1,5 = 45 kN ∑M A = 0 : By ⋅ 3 − 45 + R ⋅ 0, 75 = 0 By = 3, 75 kN ∑F y = 0: Ay + By − R = 0 Ay = 41, 25...
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This document was uploaded on 02/26/2014 for the course MECH 2300 at Delft University of Technology.

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