chap-17-2011W-b

# 8 10 10 ksp solubility product constant write the

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Unformatted text preview: −10 Ksp --- solubility product constant Write the equation for insoluble salt CaF2 : CaF2 (s) C a + (aq) + 2F - (aq) K sp = [Ca + ][ F − ]2 = 3.9 × 10 −11 17.4 17.4 Solubility Equilibrium PbCrO 4 (s) K sp Pb 2+ (aq) + C rO 4 - (aq) K sp = [ Pb 2 + ][CrO42 − ] = 2.8 × 10 −13 MgF2 (s) M g 2+ (aq) + 2F - (aq) K sp = [ Mg 2 + ][ F − ]2 Ag 2 CO 3 (s) + - 2Ag (aq) + C O 3 (aq) K sp = [ Ag + ]2 [CO32 − ] Ca3 (PO 3 ) 2 (s) 2+ 3- 3Ca (aq) + 2PO 4 (aq) 3 K sp = [Ca 2 + ]3 [ PO4 − ]2 Solubility Solubility Product Constant(Ksp)-Solubility Solubility (S): may be expressed in two ways: -- Molarity (M) of the dissolved salt --- Grams per liter (g/L) of dissolved salt The number PbCl 2 (s) K sp Pb 2+ (aq) + 2C l - (aq) K sp = [ Pb 2 + ][Cl − ]2 = 1.7 × 10 −5 P bCl 2 (s) K sp Pb 2+ (aq) + 2Cl - (aq) S 2S of moles/grams moles/grams of solute dissolved dissolved in 1 L of a of saturated saturated solution K sp = [ Pb 2 + ][Cl − ]2 = S × (2 S ) 2 = 4 S 3 = 1.7 × 10 −5 S ( mol / L ) = 3 1.7 × 10 −5 4 = 1.62 × 10 −2 M S ( g / L ) = 1.62 × 10 −2 mol / L × 278.2 g / mol = 4.50 g / L Solubility Solubility and Ksp A solution containing CaF2 (s) is allowed to reach (s) equilibrium at 25oC, and the equilibrium concentration of F- is found to be: 4.28× 10-4...
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