The two ironiii compartments are connected by a salt

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: hydrogen side and an iron(III) / iron(II) electrode on the right . The two iron(III) compartments are connected by a salt bridge and platinum is used platinum as conductor at each electrode. (b) Write a total electronic reaction for the cell (−) Pt ( s) | H 2 ( g ) | H + (aq, cH + ) || Fe3+ (aq, cFe3+ ), Fe2+ (aq, cFe2+ ) | Pt ( s)(+) H 2 ( g ) − 2e → 2 H + (aq) Fe3+ (aq) + e → Fe2+ (aq) 1 2 H 2 ( g ) + Fe3+ (aq) → H + (aq) + Fe2+ (aq) redox couple ° ° ° ° ° Ecell = Ecathode − Eanode = EFe3+ / Fe2+ − EH + / H Oxidation state 2 Reduction state state Cell EMF The difference in electrical potential between the electrical anode anode and cathode is : cathode • Electromotive Force (EMF) • Cell Potential (Ecell) •Cell Voltage (Ecell) Electromotive Force (EMF): The force required to push electrons The through the external circuit ° cell E ° cathode =E ° anode −E 1 2 H 2 ( g ) + Fe3+ (aq) → H + (aq) + Fe2+ (aq) ° ° ° ° ° Ecell = Ecathode − Eanode = EFe3+ / Fe2+ − EH + / H redox couple 2 Cell Cell EMF ° cell E ° cathode =E ° anode −E The difference in potential energy per potential electrical charge between two electrodes is measured in units of volts. volts 1J 1V= 1C A charge of one coulomb (1 C) falling though a potential difference of one volt (1 potential releases one V) releases one joule (1J) of energy. 1 V ×1C = 1J maximum its • The maxim...
View Full Document

Ask a homework question - tutors are online