Unformatted text preview: oC. Final solution at 30oC with
90% crystallization of the urea in the anhydrous form.
Assumptions: Equilibrium in the crystallizer.
Find: Fraction of water that must be evaporated.
Analysis: From Table 17.7, solubility of urea in water at 100oC = 730 g/100 g water, and
solubility of urea in water at 30oC = 135 g/100 g water
Take a basis of 1,000 kg of feed.
Therefore, have 0.90(730) = 657 g urea/100 g water
Therefore, feed is:
[657/(657 + 100)]1,000 = 868 kg urea
1,000 – 868 = 132 kg water
Urea crystals formed at 30oC = 0.90(868) = 781 kg
Urea remaining in solution = 868 – 781 = 87 kg
Therefore, water in solution = [100/135]87 = 64.4 kg
By overall mass balance, water evaporated = 132 – 64.4 = 67.6 kg
Fraction of water evaporated = 67.6/132 = 0.512 Exercise 17.13
Subject: Heat addition to the feed of a crystallizer
Given: Data from Examples 17.3 and 17.5. Crystallizer feed is 4,466 lb/h of 37.75 wt% MgSO4
in water at 170oF and 20 psia. Instead of adding 246,000 Btu/h of heat to recirculating magma in
the vacuum, evaporating crystallizer, that heat is to be added to the feed.
Assumptions: Linear extrapolation of the enthalpy chart of Figure 17.10.
Find: Exit temperature from the feed heat exchanger.
Analysis: Use the enthalpy-concentration chart for aqueous solutions of MgSO4 in Figure 17.10.
Hfeed in = -20 Btu/lb for 37.75 wt% MgSO4 at 170oF
By an enthalpy balance on the heat exchanger,
Hfeed out = -20 + 246,000/4,466 = 35.1 Btu/lb
For 37.75 wt% MgSO4, this enthalpy is off the chart of Figure 17.10. Therefore,
make a linear extrapolation, assuming a constant specific heat for the solution. For the
temperature range of 170oF to 230oF, the enthalpy change is -20 to 18 Btu/lb. Therefore,
the average specific heat = [18 – (-20)]/(230 – 170) = 0.63 Btu/lb-oF.
Using this specific heat, Tfeed out = 170 + 246,000/[4,466(0.63)] = 257oF.
This is a much higher temperature than the temperature of 85oF in the crystallizer.
Therefore, a much higher heating-medium temperature would be required. Furthermore,
the pressure of the feed would have to be increased to suppress vaporization in the heat
The conclusion is that a heat exchanger on the recirculating magma is preferred over a
heat exchanger on the feed. Exercise 17.14
Subject: Rate of heat addition to a crystallizer
Given: Data from Exercise 17.11. Feed of 5,870 lb/h of 35 wt% MgSO4 in water at 180oF and
25 psia. Recycle of 10,500 lb/h of saturated MgSO4 at 80oF and 25 psia. From calculations
made in Exercise 17.11, three phases leave the crystallizer at 85oF and 0.58 psia in the vapor
space: 1,490 lb/h of steam; 3,720 lb/h of crystals of MgSO 4 7H 2 O ; and 11,160 lb/h of a
saturated solution of 28 wt% MgSO4.
Assumptions: No heat losses from the crystallizer
Find: Rate of heat addition to the crystallizer.
Analysis: Use Figure 17.10 for enthalpies of liquid and crystals. Use steam table for steam.
An enthalpy balance around the crystallizer gives,
mfeed H feed + mrecycle H recycle + Qin = msteam H steam + mli...
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This document was uploaded on 02/24/2014 for the course CBE 2124 at NYU Poly.
- Spring '11
- The Land