Separation Process Principles- 2n - Seader & Henley - Solutions Manual

Separation Process Principles 2n Seader& Henley Solutions Manual

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Unformatted text preview: + 0.030(0.124)]/1.524 = 0.468/1.524 = 0.307 lb H2O/lb silica gel. Thus, 0.307/0.440 x 100% = 70% utilization of the bed. Exercise 15.26 (continued) Analysis: (continued) Concentration profiles 1.0 0.9 0.8 0.7 c/c F 0.6 0.5 0.4 0.3 0.2 0.1 0.0 0 100 200 300 400 Time, minutes 500 600 700 Analysis: (continued) Exercise 15.26 (continued) Loading Profiles 1.0 0.9 0.8 0.7 q bar/q F * 0.6 0.5 0.4 0.3 0.2 0.1 0.0 0 100 200 300 400 Time, minutes 500 600 700 Exercise 15.27 Reduction of nitroglycerine (NG) content of wastewater by fixed-bed adsorption Subject: with activated carbon in a train of 55-gallon cannisters Given: Train of four 55-gallon cannisters of activated carbon (ρb = 32 lb/ft3), each with an inside diameter of 2 ft and containing 200 lb of carbon. Flow rate of wastewater = 400 gph with 2,000 ppm (by weight) of NG. When effluent from the first cannister reaches 1 ppm of NG, that cannister is removed and a fresh one added to the end of the train. The following test results are available for one cannister: water flow rate = 10 gpm with 1,020 ppm of NG by weight. Breakthrough time in hours = tB = 3.90 L - 2.05 for 1ppm NG, with L = bed depth in ft. Assumptions: Plug flow. Find: Number of cannisters needed each month. Monthly cannister cost at $700/cannister. Analysis: Bed volume of activated carbon = 200/32 = 6.25 ft3 = V = πD2L/4. Solving for L, with D = 2 ft, gives L = 2 ft. Rearrange the breakthrough correlation for the test, by solving for L, L = tB/3.90 + 2.05/3.90 = 0.256 tB + 0.526 This is the same form as Eq. (15-120), where the term 0.256 tB is LES and the term 0.526 is LUB. Assume that the width of the MTZ = constant, independent of flow rate. Therefore, LUB is constant at 0.526 ft. From Eq. (15-122), LES is directly proportional to the feed rate, QF . If a linear adsorption isotherm is assumed, then LUB is independent of the ratio qF/cF in Eq. (15-122). That is, for the proposed operation, the higher value of cF (2,000 ppm compared to 1,020 ppm for the test) is of no consequence. The higher concentration of NG in the feed, cF, is couterbalanced by the higher loading in equilbrium with the feed, qF. The breakthrough equation becomes: L = 0.256 QF of operation 400 t B + 0.526 = 0.256 t B + 0.526 = 0.171t B + 0.526 QF of test 600 Solving for tB, with L of operation also equal to 2 ft, tB = L − 0.526 = 586 L − 3.08 = 586(2) − 3.08 = 8.64 hours = 8.64/24 = 0.36 day . . 0.171 Assume a month of 30 days. Then need 30/0.36 = 84 cannisters per month. Cost = $700(84) = $58,800/month Exercise 15.28 Subject: Sizing of fixed-bed adsorption unit for removal of ethyl acetate (EA) from air with activated carbon (C), using adsorption equilibrium isotherm and breakthrough data Given: Gas feed is 12,000 scfm (60oF and 1 atm) containing 0.5 mol% EA and 99.5 mol% air. Adsorbent is C (ρb = 30 lb/ft3 and dp = 0.011 ft. Adsorption equilibrium data at 100oF. Breakthrough lab data at a gas superficial velocity of 60 ft/min in a 2-ft high bed at 100oF and 1 atm. Assumptions: Plug flow. Find: Diameter and h...
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This document was uploaded on 02/24/2014 for the course CBE 2124 at NYU Poly.

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