Unformatted text preview: ing from the upper line, which passes through the point x = 0.96 on the
45o line. Equilibrium stages are stepped off starting from the distillate composition and
switching operating lines at the appropriate times to determine the optimal feed stage and
sidestream stage locations. A separate McCabeThiele diagram is used for the upper section to
achieve better accuracy. As seen 19 equilibrium stages plus a partial reboiler are required. The
optimal feed stage is 9 from the top and the optimal sidestream stage is 17 from the top. Analysis: (continued) Exercise 7.36 (continued) Exercise 7.37
Subject:
Distillation at 1 atm of a mixture of toluene and phenol for a given boilup ratio,
with an alternative using an interreboiler.
Given: 1,000 kmol/h of a saturated liquid feed of 25 mol% toluene. Distillate is 98 mol%
toluene and bottoms is 2 mol% toluene. The base unit consists of a total condenser, a plate
column, and a partial reboiler, with a boilup ratio, VB = V / B = 1.15 times minimum. The
alternative unit adds an interreboiler midway in the stripping section to provide 50% of the
boilup. A table of Tyx phase equilibrium data
Assumptions: Constant molar overflow.
Find: For each unit, determine the number of theoretical stages. For the alternative unit,
determine the temperature of the interreboiler stage.
Analysis: Toluene is the more volatile unit.
Base unit:
From the McCabeThiele diagram below, the minimum boilup ratio is determined from
the slope of the stripping section operating line that intersects the equilibrium curve at the feed
composition of xF = 0.25. ( L /V ) min = 0.815 − 0.02
= 3.46
0.25 − 0.02 From Eq. (728), (VB )min = 1 ( L /V ) min −1 = 1
= 0.407
3.46 − 1 Exercise 7.37 (continued) Analysis: Base Case (continued) For column operation, VB = 1.15(VB)min = 1.15(0.407) = 0.468
From Eq. (712), the slope of the stripping section operating line is,
V + 1 0.468 + 1
L /V = B
=
= 314
.
VB
0.468
As shown in the McCabeThiele diagram, below, a line of this slope is drawn through the point
x = y = 0.02 until it intersects the qline. Equilibrium stages are stepped off, starting from the
distillate point at y = x = 0.98. The optimal feed stage location is located as shown at stage 5
from the top. The total number of stages required is just less than 8, with one of those stages
being the partial reboiler. Exercise 7.37 (continued)
Analysis: Base Case (continued) Exercise 7.37 (continued)
Analysis: (continued)
Alternative unit with Interreboiler:
For column operation with an interreboiler that provides 50% of the reboiler duty, the
operating boilup ratio between the reboiler and the interreboiler is 50% of 0.468 or 0.234.
From Eq. (712), the slope of the operating line in this region is:
L /V = VB + 1 0.234 + 1
=
= 5.27
VB
0.234 Between the interreboiler and the feed stage, the slope of the operating line remains at 3.14,
based on a material balance around the column section from the bottoms to the region between
the interreboiler and the f...
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 Spring '11
 Levicky
 The Land

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