Unformatted text preview: ne/ kg solventfree extract and 5.7 wt% MCH in the
extract. This gives 14.5/15.5 x 100% = 93.5 wt% aniline. A total material balance around the
bottom Mixer gives:SB  B = 11,830  540 = 11, 290 = VB  L1 .
An aniline balance around the bottom Mixer gives:11,830  40 = 0.935VB  0.075L1.
Solving these two equations gives L1 = 1,435 kg/h.
Therefore, the raffinate reflux ratio = (1,435  540)/540 = 1.66. Exercise 8.28
Subject: Design of a mixersettler unit for extraction of acetic acid (A) from water (C) by
isopropyl ether (S).
Given: 12,400 lb/h of 3 wt% A in C. 24,000 lb/h of S. 1.5 minutes residence time in mixer. 4
gal/minft2 in settling vessel.
Find: (a)
(b)
(c)
(d) Diameter, DT , and height, H, of mixing vessel if H/DT = 1.
Agitator Hp for mixing vessel.
Diameter, DT , and length, L, of settling vessel, if L/DT =4.
Residence time in settling vessel in minutes. Analysis: First compute total volumetric flows into mixer vessel. Because feed is dilute in A,
assume density of feed is that of water = 62.4 lb/ft3. From Perry's Handbook, specific gravity of
S = 0.725 or a density of 0.725(62.4) = 45.2 lb/ft3. Therefore, total flow rate of feed plus solvent
=
Q = 12,400/62.4 + 24,000/45.2 = 730 ft3/h or 12.2 ft3/min.
(a) Vessel volume = V = Qtres = 12.2(1.5) = 18.3 ft3
For a cylindrical vessel of H/DT = 1, V = πDT2H/4 = πDT3/4
Solving, DT3 = 4V/π = 4(18.3)/3.14 = 23.3 ft3. Therefore, DT = H = 2.85 ft
(b) Assume 4 Hp/1,000 gallons for mixer agitator power.
Gallons in vessel = 7.48V = 7.48(18.3) = 137 gal
Therefore, need 4(137)/1,000 = 0.55 Hp.
(c) Assume volumetric flow into mixer = volumetric flow leaving settler
Therefore, Q = 12.2 ft3/min or 7.48(12.2) = 91 gpm
The ft2 disengaging area needed = 91/4 = 22.8 ft2 = DTL = DT(4DT) = 4DT2
Solving, DT = 2.4 ft and L = 4DT = 4(2.4) = 9.6 ft.
(d) Settler volume = V = πDT2L/4 = 3.14(2.4)2(9.6)/4 = 43.4 ft3
Residence time of phases in settler = tres = V/Q = 43.4/12.2 = 3.6 minutes Exercise 8.29
Subject: Extraction of acetic acid (A) from water (C) by ethyl acetate (S) in available extractor.
Given: Cascade of 6 mixersettler units. Each mixer is 10ft diameter by 10ft high with 20Hp
agitator. Each settler is 10ft diameter by 40ft long. Feed and solvent compositions , and
solventtofeed mass ratio, are those in Fig. 8.1.
Find: Allowable feed flow rate.
Analysis: From Fig. 8.1, the total entering component flow rates are as follows, with liquid
densities from Perry's Handbook. Assume ideal liquid solutions.
Component lb/h Acetic acid
Water
Ethyl acetate 6,660
26,100
68,600 density,
lb/gal
8.74
8.33
7.51 gpm
12.7
52.2
152.2 Therefore, total flow rate = Q = 12.7 + 52.2 + 152.2 = 217.1 gpm
The volume of one mixer = V = πDT2H/4 = 3.14(10)2(10)/4 = 785 ft3 or 5,872 gal.
First consider the mixer residence time factor.
With the flow rates in Fig. 8.1, residence time in mixer = tres = V/Q = 5,872/217 = 27 minutes.
Since the liquid phase viscosities are each less than 5 cP (actually less than 1 cP) and the de...
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This document was uploaded on 02/24/2014 for the course CBE 2124 at NYU Poly.
 Spring '11
 Levicky
 The Land

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