Separation Process Principles- 2n - Seader & Henley - Solutions Manual

Initial impurity concentration is uniform at wo

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: n density data in Fig. 17.37, which do not fit (17-38). Assumptions: Equilibrium Find: (a) An empirical equation that does fit the crystal population density data. (b) Whether and how nucleation rate and growth rate can be determined from the data. Analysis: (a) From Fig. 17.37, values of n in nuclei/m-m3 for crystal sizes L are read and listed in the table below. Using the nonlinear regression feature of Polymath, a number of different expressions were tried for fitting the data. The best fit, which was not entirely satisfactory, giving an R2 of 0.986, was: ln n = 40.08 exp(0.00124 L – 0.06075 L0.5) The following spreadsheet compares the data points to the predictions of the correlation. Data: Crystal size, L, microns Correlation: n, no./m-m3 ln n ln n n 3 4 6 9 12 18.5 26 37 53 74 1.30E+16 1.90E+15 8.80E+14 4.50E+14 8.80E+13 4.80E+13 3.00E+13 6.00E+12 6.20E+11 2.00E+11 37.10 35.18 34.41 33.74 32.11 31.50 31.03 29.42 27.15 26.02 36.21 35.67 34.80 33.78 32.96 31.58 30.37 29.00 27.50 26.05 5.32E+15 3.10E+15 1.29E+15 4.67E+14 2.06E+14 5.18E+13 1.54E+13 3.92E+12 8.80E+11 2.06E+11 A comparison of the data to the prediction by the correlation is given on the next page. Exercise 17.28 (continued) 1.E+17 Crystal Population Density, no./m-m3 1.E+16 ____________ Data - - - - - - - - Correlation 1.E+15 1.E+14 1.E+13 1.E+12 1.E+11 0 10 20 30 40 50 60 70 80 Crystal size, microns (b) Because the correlation is not of the form of (17-38), the theory in Section 17 .6 cannot be used to predict nucleation rate and growth rate. Exercise 17.29 Subject: Precipitation of Mg(OH)2 from mixing of aqueous solutions of MgCl2 and Ca(OH)2 in an MSMPR crystallizer. Given: Crystallizer volume = 1 L. Operation at 450 rpm and 25oC. Measured crystal size given in Fig. 17.38 for 5 minutes residence time. Assumptions: Crystal size is proportional to exp(-L/Gτ) as in (17-38). Assume that n in Fig. 17.38 has units of no./micron-L. Find: (a) Growth rate, G (b) Nucleation rate, Bo (c) Predominate crystal size, Lpd Analysis: (a) From (17-52), Bo L n= exp − G Gτ or in a straight-line form, Bo L log n = log − G 2.303Gτ (1) Take end points of the line in Fig. 17.38 as: n = 90 at L = 0.55 and n = 3 at L = 1.35 Substituting these two data points into (1) with τ = 5 minutes, and solving, gives G = 0.047 microns/min (b) With this value of G, substitution into (1) for either data point gives, Bo = 44 nuclei/L-min. (c) From (17-49), Lpd = 3Gτ = 3(0.047)(5) = 0.705 micron Exercise 17.30 Subject: Melt crystallization of naphthalene from a mixture with benzene in a falling-film crystallizer. Given: Feed of 60 wt% naphthalene and 40 wt% benzene at saturation conditions. Coolant enters at top at 10oC. Physical property data from Example 17.13. Assumptions: Equilibrium. Crystallization on a planar wall. Find: Crystal layer thickness for up to 2 cm as a function of time. Analysis: Assume the major resistance to heat transfer is the crystal layer building up on the wall. Let ri - rs = thickness of the crystal layer F...
View Full Document

This document was uploaded on 02/24/2014 for the course CBE 2124 at NYU Poly.

Ask a homework question - tutors are online