Separation Process Principles- 2n - Seader & Henley - Solutions Manual

Such a correlation since it would be empirical would

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Unformatted text preview: . 0.60 0.40 111 − 1 . = 14.75 Use either the Gilliland graphs of Figs. 9.10 or 9.11, or the Gilliland correlation equation, (9-34). The latter is more accurate, but requires iteration when solving for X. Apply the equation. N − N min 144.4 − 72.2 Y= = = 0.497 N +1 144.4 + 1 Using a spreadsheet to solve Eq. (9-34), which is nonlinear in X, we obtain X = 0.159 R − Rmin X= = 0.159 Solving, R = 17.73 and R/Rmin = 17.73/14.75 = 1.202 R +1 Exercise 9.14 Subject: Number of equilibrium stages by the FUG method for the distillation of a binary mixture of dichlorobenzene (DCB) isomers. Given: Feed of 62 mol% p-DCB and 38 mol% o-DCB at approximately 1 atm. Distillate to contain 98 mol% p-DCB, and bottoms to contain 96 mol% o-DCB. Total condenser and partial reboiler. Average relative volatility = 1.154 with the para isomer as the LK. Feed condition is q = 0.9 (10 mol% vaporized). Want R/Rmin = 1.15. Assumptions: External reflux ratio = internal reflux ratio at the upper pinch. Find: Number of equilibrium stages by the FUG method. Analysis: Using the Fenske equation (9-11): log N min = xp-DCB D xp-DCB B xo-DCB B xo-DCB D log α p-DCB,o-DCB log = (0.98) 0.96 (0.04) 0.02 log(1154) . = 49.3 For minimum reflux, use the Class 1 Underwood equation (9-20), which applies for a binary mixture, where the pinch composition is that of the liquid portion of the feed. From the feed composition, determine the equilibrium liquid composition by a flash calculation for 10 mol% vaporization. Do this by combining Eqs. (7-26) for the q-line with (4-8) for equilibrium at a constant relative volatility. Thus, applying these equations to the LK, p-DCB, αx 1154 x . q zF 0.62 = = x− = −9 x + = 6.2 − 9 x 1 + x (α − 1) 1 + 0154 x . q −1 q −1 01 . Solving this nonlinear equation for a positive root of x between 0 and 1 gives x = xp-DCB = 0.617 Then, xp-DCB, D Rmin = Lmin = D xp-DCB, F − α p − DCB,o − DCB α p − DCB,o − DCB − 1 xo-DCB, D xo − DCB, F = 0.98 0.02 . − 1154 0.617 0.387 1154 − 1 . = 9.93 R = 1.15 Rmin =1.15(9.93) = 11.42 In the Gilliland equation, (9-34), X = (R - Rmin)/(R + 1) = (11.42-9.93)/(11.42+1) = 0.120. Using Eq. (9.34), Y = 0.534 = (N - Nmin)/(N + 1). Solving, N = 107 stages. Exercise 9.15 Subject: Shortcomings of the Gilliland correlation Given: Column with a small ratio of rectifying to stripping stages. Find: Explanation for possible inapplicability of the Gilliland correlation. Analysis: When a column has a small ratio of rectifying to stripping stages, stripping of a light key in the stripping section may dominate over absorption of the heavy key in the rectifying section, in determining stage requirements. The Gilliland correlation is based on reflux considerations in the rectifying section. Alternatively, a correlation could have been developed based on boilup considerations in the stripping section, using a modified Underwood equation for minimum boilup ratio. Such a correlation, since it would be empirical, would seem to...
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This document was uploaded on 02/24/2014 for the course CBE 2124 at NYU Poly.

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