Quiz 8 Solution

Thus we skip h2 and continue until we find a coset

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Unformatted text preview: enerated by element 0. Thus we skip H2 and continue until we find a coset containing elements we haven’t covered yet. In this case, we end up with cosets generated by 0, 1, 8 and 9. 0 * H = {0, 2, 4, 6} = 0 = H0 or [0] 1 * H = {1, 3, 5, 7} = 1 = H1 or [1] 8 * H = {8, 10, 12, 14} = 8 = H8 or [8] 9 * H = {9, 11, 13, 15} = 9 = H9 or [9]...
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This document was uploaded on 02/26/2014 for the course ECE 490SIC at Drexel.

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