quiz2solutions

Quiz2solutions

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Unformatted text preview: #### ######### 2 ######## E He- L = Hm c2 L + H pe cL2 = K + m c2 which yields !!!!!!!!!!!! 1 è !!!!!!!!!!!!!!!! pe = ÅÅÅÅ K 2 + 2 K m c2 c which means that we have p1,x ! !!!!!!!!!!!! 1 è!!!!!!!!!!!!!!!! MeV Ø p1,x = ÅÅÅÅÅcÅÅ K 2 + 2 K m c2 º 0.711 ÅÅÅÅÅÅÅÅÅÅÅÅ 2 c How do we find p1,y then? We can use the energy E1 to find the magnitude p1 , 11 p1 = E1 ê c = ÅÅcÅÅ H ÅÅÅÅ K + m c2 L 2 2 2 2 and then use p x + p y = p and solve for p1,y p1,y 2 = p1 2 - p1,x 2 1 1 1 = ÅÅÅÅÅÅ H ÅÅÅÅ K + m c2 L - H ÅÅÅÅÅcÅÅ L HK 2 + 2 K m c2 L c2 2 2 2 1 1 = ÅÅÅÅÅÅ I ÅÅÅÅ K m c2 + Hm c2 L M c2 2 2 2 2 #### 1 1 MeV 2 p1,y = ÅÅcÅÅ "################ + Hm c2 L ## º 0.718 ÅÅÅÅÅÅÅÅÅÅÅ ÅÅÅÅ K m c################ Å 2 c From what we said before about the other g, !!!!!!!!!!!! 1 è!!!!!!!!!!!!!!!! p2,x = ÅÅÅÅÅcÅÅ K 2 + 2 K m c2 2 2 #### 1 1 2 p = - ÅÅÅÅ "################ + Hm c2 L ## ÅÅÅÅ K m c################ Finally, Ø 2,y (d) c 2 Finally, to obtain q, we just use the relation py tan q = ÅÅÅÅ1,ÅÅÅÅ Å p 1, x Substituting the numbers from above gives 0.718 tan q = ÅÅÅÅÅÅÅÅÅÅÅÅÅ º 1.011 0.711 q º 0.79 radians º 45 ° This of course makes sense, since p y º px (look at the sketch). 2. Trapping Antim...
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This document was uploaded on 02/26/2014 for the course PHYS 2D at UCSD.

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