quiz2solutions

1 1 e1 e2 etotal k m c2 1011 mev 2 2 b c here

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Unformatted text preview: 1 E1 = E2 = ÅÅÅÅ Etotal = ÅÅÅÅ K + m c2 º 1.011 MeV 2 2 (b) (c) Ø Here is what you should already know: p1,y = - p2,y (1) p1,x = p2,x (2) So you only need to solve for the momentum of one of the g rays. It's a good idea to start with conservation of momentum. p1,x + p2,x = pfinal = pe (3) Combining (2) and (3) gives 1 p1,x = ÅÅÅÅ pe (4) 2 We can find pe from K using "################ ######### 2 ######## E He- L = Hm c2 L + H pe cL2 = K + m c2 which yields !!!!!!!!!!!! 1 è !!!!!!!!!!!!!!!! pe = ÅÅÅÅ K 2 + 2 K m c2 c which means that we have p1,x ! !!!!!!!!!!!! 1 è!!!!!!!!!!!!!!!! MeV p1,x = ÅÅÅÅÅcÅÅ K 2 + 2 K m c2 º 0.711 ÅÅÅÅÅÅÅÅÅÅÅÅ 2 c How do we find p1,y then? We can use the energy E1 to find the magnitude p1 , 11 p1 = E1 ê c = ÅÅcÅÅ H ÅÅÅÅ K + m c2 L 2 2 + p 2 = p2 and solve for p and then use p 1 1,x 2, x final e Combining (2) and (3) gives 1 p1,x = ÅÅÅÅ pe (4) 2 We can quiz2solns.nb find pe from K using "############...
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This document was uploaded on 02/26/2014 for the course PHYS 2D at UCSD.

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