exp 1 - densities of liquids and solids

exp 1 - densities of liquids and solids - Results and...

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Results and Discussion: The densities of an unknown solid and an unknown liquid were found by using methods of water displacement for the solid and obtaining the mass of the liquid by using a balance. Two experimental trials were performed for both the solid and the liquid. The data was put into two tables (Table 1 and Table 2). Table 1: Unknown solid #4 – Mass of solid: 10.222 g Trial # Volume of water Volume of water + solid Volume of solid Density Trial 1 14.50 ml 18.50 ml 4.00 ml 2.56 g/ml Trial 2 12.50 ml 16.20 ml 3.70 ml 2.76 g/ml The volume of the unknown solid was calculated by subtracting the volume of only the water in the graduated cylinder from the volume of the water plus the solid. The density was calculated by dividing the grams and the volume of the solid. An example of the calculation using trial #1 follows: To obtain the volume of the solid, 18.50 ml – 14.50 ml = 4.00 ml To calculate the density, 10.222 g / 4.00 ml = 2.56 g/ml According to a given table, aluminum with a density of 2.7 g/ml was found to have the
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This note was uploaded on 02/11/2008 for the course CHEM 2070 taught by Professor Chirik,p during the Spring '05 term at Cornell.

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exp 1 - densities of liquids and solids - Results and...

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