00 in a savings account at a bank yielding 11 per

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Unformatted text preview: ∙ 3) + 3 = 2 + 2 ∙ 3 a4 = a3 +3 = (2 + 2 ∙ 3) + 3 = 2 + 3 ∙ 3 . . . an = an - 1 + 3 = 2 + (n – 1) ∙ 3 Itera$ve Solu$on Example Method 2: backward substitution Let {an} be a sequence that satisfies the recurrence relation an = an - 1 + 3 for n = 2, 3, 4, … and suppose that a1 = 2. an = an - 1 + 3 = an - 1 + 1 ∙ 3 = (an - 2 + 3) + 1 ∙ 3 = an - 2 + 2 ∙ 3 = (an - 3 + 3 ) + 2 ∙ 3 = an - 3 + 3 ∙ 3 . . . = an - ( n - 1 ) + (n - 1) ∙ 3 = a1 + (n - 1) ∙ 3 = 2 + (n - 1) ∙ 3 Financial Applica$on Example: suppose that a person deposits $10,000.00 in a savings account at a bank yielding 11% per year...
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This document was uploaded on 02/27/2014 for the course CS 215 at SIU Carbondale.

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