L3940_memtrans_462A_2013sm

0 mv s outside s01 nm 80

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Unformatted text preview: = –30 kJ/mol + (8.314 J/mol K)(310 K) ln ((.001 M)(.0005 M) / (.003 M)) = –30 kJ/mol + –22.5 kJ/mol = –52.5 kJ/mol Electrochemical PotenGals Difference in concentraGon between the interior and exterior of a cell: chemical potenGal High Concentra4on C2 C1 Low Concentra4on Concentra4on Gradient Difference in voltage between the interior and exterior of a cell: electrical potenGal + +  ­ + V1 Charge Gradient: Voltage Difference V2 transmembrane poten4al = Electrochemical PotenGals Difference in concentraGon between the interior and exterior of a cell: chemical potenGal High Concentra4on C2 C1 Low Concentra4on Concentra4on Gradient Difference in voltage between the interior and exterior of a cell: electrical potenGal + +  ­ + V1 Charge Gradient: Voltage Difference V2 transmembrane poten4al = Transport against Voltage (electropotenGal) For this quesGon, we will define the process as Inside Outside 0 mV (high) + –65 mV (low) ΔV = V2 (desGnaGon) – V1 (origin) = ΔGelec = Z F ΔV F=96.5 kJ/(mol V) (Faraday Constant) Transport against concentraGon gradient (chemical potenGal) C1 (origin) = x C2 (desGnaGon) = 25 mM ΔGchem = RT ln (C2/C1) + 25 mM (high) + + + + x (low) T=310K R = 8.314 J/(mol K) (Gas Constant) Coupled reacGon ΔGelec + ΔGchem + ΔGATP Free energy change of transport Diffusion of a substance between two sides of a membrane C1 < ­ ­ ­ ­ ­> C2 ΔV = V2 – V1 C1 V1 ΔG = elec...
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This test prep was uploaded on 02/25/2014 for the course BIOC 462A taught by Professor Ziegler,baldwin during the Spring '08 term at University of Arizona- Tucson.

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