C ab n ab n ab v so if the number of moles of each

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Unformatted text preview: + B–(aq). The equilibrium constant KC (ignoring the standard concentration terms for simplicity) is given by: KC = c A + % c B − (n A + / V ) % (n B − / V ) n A + % n B − 1 = = % V. c AB n AB (n AB /V ) So, if the number of moles of each species remained the same, as the system is diluted, the equilibrium constant decreases. Since this cannot happen (KC is a constant at a given temperature), the number of moles of A+(aq) and B–(aq) must increase with increasing volume. (b) change in pressure: Consider the reaction N2(g) + 3H2(g) W 2NH3(g). Similar arguments as above can be made for KP as pressure is changed. However, it is sufficient to note that there are 4 moles of gases on the reactant sid...
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