{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Lecture 3 - Galilean velocity transformation u x-3-2-1 0 1...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
1 Galilean velocity transformation If an object has velocity u in frame S (note: velocities have a direction!) , and if frame S’ is moving with velocity v along the positive x-axes of frame S, then the position of the object in S’ is: v t t x t x ) ( ) ( ' ... -3 -2 -1 0 1 2 3 ... ... -3 -2 -1 0 1 2 3 ... v u x x’ The velocity u of the object in frame S’ is therefore: A) u + v B) v - u C) u - v D) u E) -v Announcements Reading for Monday (due noon) : TZD 1.7- 1.9 Homework #1 is due at noon, Wednesday this week (in ‘2130’ box in G2B90). Today Maxwell vs. Galileo Strange things about the speed of light Mr. Maxwell told us, the speed of light ‘ c ’ is: s m c / 10 00 . 3 1 8 0 0 Mr. Galileo told us that c’ = c – v If the laws of physics are the same in all inertial frames then ε 0 and μ 0 (and c ) have to be the same in all inertial frames. So let’s make up the “luminiferous ether” to fix Galileo’s velocity transformation law (u’ = u - v)! (We will have to check if there is a luminiferous ether!..) Last class we found a problem!! Peculiar light-waves A sound wave propagates through air, with a velocity relative to the air (~330 m / sec) A water wave propagates through water, with a velocity relative to the water (1..100 m / sec) • “The wave” propagates through a crowd in a stadium, with a velocity relative to the audience. An electromagnetic wave propagates through... Answer (19 th century physics): The “luminiferous ether.” Ideas behind Einstein’s relativity Is there an ether ?
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern