Shortest path costs the rst node we will add to s is

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: g order of CHAPTER 18. NETWORK ROUTING - I 12 WITHOUT ANY FAILURES Figure 18-6: Dijkstra’s shortest paths algorithm in operation, finding paths from A to all the other nodes. Initially, the set S of nodes to which the algorithm knows the shortest path is empty. Nodes are added to it in non-decreasing order of shortest path costs, with ties broken arbitrarily. In this example, nodes are added in the order (A, C, B, F, E, D, G). The numbers in parentheses near a node show the current value of spcost of the node as the algorithm progresses, with old values crossed out. shortest-path costs. The first node we will add to S is n itself, since the cost of the path from n to itself is 0 (and not larger than the path to any other node, since the links all have non-negative weights). Figure 18-6 shows an example of the algorithm in operation. Fortunately, there is an efficient way to determine the next node to add to S from the set X . As the algorithm proceeds, it maintains the current shortest-path costs, spcost(v ), for each node v . Initially, spcost(v ) = ∞ (some big number in practice) for all nodes, except for n, whose spcost is 0. Whenever a node u is added to S , the algorithm checks each of u’s neighbors, w, to see if the current value of spcost(w) is larger than spcost(u) + linkcost(uw). If it is, then update spcost(w). Clearly, we don’t need to check if the spcost of any other node that isn’t a neighbor of u has changed because u was added to S —it couldn’t have. Having done this step, we check the set X to find the next node to add to S ; as mentioned before, the node with the smallest spcost is selected (we break ties arbitrarily). The last part is to remember that what the algorithm needs to produce is a route for each destination, which means that we need to maintain the outgoing link for each destination. To compute the route, observe that what Dijkstra’s algorithm produces is a shortest path tree rooted at the source, n, traversing all the destination nodes in the network. (A tree is a graph that has no cycles and is connected, i.e., there is exactly one path betw...
View Full Document

This document was uploaded on 02/26/2014 for the course CS 6.02 at MIT.

Ask a homework question - tutors are online